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Let the molecular masses of A and B be MA and MB.Applying ideal gas equation            PV = nRT.For ideal gas A:        PAV = nARTFor ideal gas B:
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Maximum voltage that can be applied across the galvanometer coil = 100 Ω x 10-3 A = 0.1If Rs is the shunt resistance, thenRs x 10 A = 0.1 VRs = 0.01 Ω

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स्वतंत्रता की नकारात्मक औ

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Jharkhand Board - Hindi Medium NCERT solutions for Class 8.Get free online study material for Class 8.Find NCERT solutions textbook questions and answers and download NCERT books from Zigya Book-Store.
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ફ્રાન્સના સમાજવિજ્ઞાની ઑગસ્ટ કૉંતને ‘સમાજશાસ્ત્રના અદ્યસ્થાપક’ કે ‘સમાજશાસ્ત્રના પિતા’ ગણવામાં આવે છે. તેઓ ‘સમાજશાસ્ત્ર’ શબ્દનો ઉપયોગ કરનાર પ્રથમ વિદ્વાન વ્યક્તિ હતા. કૉંતનો જન્મ ફ્રાન્સના મોન્ટ પેલિયર ખાતે 19 જાન્યુઆરી, 1798ના રોજ પરંપરાવાદી કૅથલિક કુટુંબમાં થયો હતો.તેમણે પ્રાથમિક શિક્ષણ તેમજના ગામમાં જ લીધું હતું અને ઉચ્ચ શિક્ષણ પૅરિસની ‘ઇકોલે પૉલિટેકનિક’ માં લીધું હતું. ઑગસ્ટ કૉંત્ના છ ખંડમાં પ્રકાશિત થયેલા પુસ્તક ‘Positive Philosophy’ માં સમાજશાસ્ત્રને એક સ્વતંત્ર સામાજિક વિજ્ઞાન તરીકે રજૂ કરવામાં આવ્યું છે. તેમાં ત્રણ તબક્કાનો સિદ્વાંત, વિજ્ઞાનનું વર્ગીકરણ, પ્રત્યક્ષવાદ, સામાજિક સ્થિતિશા
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Find CBSE, ICSE State Boards Textbook Solutions of Class 8 to 12 of all subjects. Read NCERT Textbooks Questions and Answers & Find Previous year solved papers.
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1.25 molal NaOH solution means, 1.25 moles of NaOH are present in 1000 gm of water.∴ Weight of NaOH = 1.25 × 40 = 50 gmWeight of solution = 1000 + 50 = 1050 gm%(by weight) of NaOH = wt. of solutewt. of solution × 100                                  = 501050 × 100                                  = 4.76 %
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The number of rose plants in the rows are 23, 21, 19, .......... 5Here, a = 23, d = –2, an = 5We know that,an = a + (n – 1)d⇒ 5 = 23 + (n – 1) (–2)⇒ 5 = 23 – 2n + 2⇒ 5 = 25 – 2n⇒ 2n = –20⇒ n = 10Hence, there are 10 rows in the flower bed.
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The reaction for which the number of moles of gaseous products (np) is not equal to the number of moles of gaseous reactants (nR), has a different value of Kc and Kp.a) np = nR = 2 thus, Kp = Kcb) np = nR = 2 thus, Kp = Kcc) np = nR = 2 thus, Kp = Kcd) np = 2, nR = 1 thus, Kp not equal to Kc
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Cr2O72- → Cr3+ (Change in +3)Oxidation number = + 6Total change in number of electrons = 2 × 3 = 6 mole = 6F
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Hofmann-bromamide degradation reaction is given asRCONH2 + 4 NaOH + Br2 → RNH2 + Na2CO3 + 2NaBr + 2H2OHence four moles of NaOH and one mole of Br2 are used.
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Degree of dissociation, Where, and  are equivalent conductances at a given concentration and at infinite dilution respectively.From Ostwald s dilution law (for weak monobasic acid)
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Resistances of both the bulbs areHence, R1 >R2When connected in series, the voltages divide in them in the ratio of their resistances. The voltage of 440 V divide in such a way that voltage across 25 w bulb will be more than 220 V. Hence 25 w bulb will fuse.
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Let r and R be respectively the radii of upper portion of cone and whole cone, and h and H be their respective heights.And let l and L be respectively the slant heights of upper portion of cone and whole cone.It is given that :
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Since D of D2O gets attached to the carbon atom to which MgBr is attached, C is isopropylmagnesium bromide
Therefore, the compound R-Br is 2- bromopropane
When an alkyl halide is trated with Na in the presence of ether, a hydrocarbon containing double bond the number of carbon atom as present in the original halide is obtained as product. This is known as Wurtz raction.

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7, 13, 19, ... , 205यहाँ, a = 7d = 13 - 7 = 6an = 205माना पदों की संख्या = nतब, an = 205 a + ( n - 1) d = 205 7 + ( n - 1)6 = 205 6(n - 1) = 205 - 7 6(n - 1) = 198 n - 1 = 33 n = 33 + 1 n = 34अत: दी हुई A.P. में 34 पद हैं।
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Characteristics of the periodical markets:
1. These markets are held weekly or fortnightly at a particular place.
2. In villages, the periodical markets are called by different names such as penth etc.  In these periodical markets the local items are sold and purchased by the local people.
3. Mostly daily used articles are sold in these markets. Different articles are sold on cheap rates as the purchasers belong to the village people.
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Angle of prism, A = 60o Refractive index of prism = 1.5 Given, angle of incidence , i1=i2 = 34A = 3445o = 45oAs,                    A + δ = i1 + i2 ⇒                60o + δ = 45o + 45o Then, angle of minimum deviation, δ =  90o - 60o                                                           = 30o We know that, velocity of light in vacuum = 3×108 m/s Now, using the formula,                 μ = sin (A+δm)/2sin A/2 = cvThat is,                  v = c sin A/2sin (A+δm)/2   = 3× 108  sin 30osin (60o + 30o)/2    = 3× 108 sin 30osin 45o    =  3× 108 ×0.50000.7071   = 2.12 × 108 m/s   is the required
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1. ‘We’ stands for the Goan children.2. They didn’t care much about brushing and cleaning teeth and mouths because they were lazy and careless.3. Plucking.