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The percentage (by weight) of sodium hydroxide in a 1.25 molal NaOH solution is

priyapatel (#38) 625 days ago News jee previous year papers 2009 All https://www.zigya.com   Discuss  Published New Discard Success!

1.25 molal NaOH solution means, 1.25 moles of NaOH are present in 1000 gm of water.∴ Weight of NaOH = 1.25 × 40 = 50 gmWeight of solution = 1000 + 50 = 1050 gm%(by weight) of NaOH = wt. of solutewt. of solution × 100                                  = 501050 × 100                                  = 4.76 %